计算无穷级数，单精度时的收敛情况。
n = 0;
sum = single(0);
while(1)
n = n + 1;
if mod(n, 100000) == 0
disp(num2str(n));
end
if(sum + single(1/n) == sum)
break;
end
sum = sum + single(1/n);
end
disp(['Single precision: ' 'n = ' num2str(n)]);n = 0;
sum = single(0);
whi
