How would you use set! in a simple procedure f such that evaluating (+ (f 0) (f 1)) will return 0 if the arguments to + are evaluated from left to right but will return 1 if the arguments are evaluated from right to left?How would you use set! in a simple procedure f
阅读背景：
怎么用套装！在Scheme函数？
来源：互联网
分享到：
