我可以调用一个方法w/o，在c++中传递所需的参数。如何来吗?

Here is the code...

这是代码…

#include "stdafx.h"
#include<iostream>
using namespace std;

class Base
{
public:
    virtual void Display(bool b = false)
    {
        cout<<"Base"<<"\t"<<b<<endl;
    }
};

class Derived : public Base
{
public:
    virtual void Display(bool b) override
    {
        cout<<"Derived"<<"\t"<<b<<endl;
    }
};

int _tmain(int argc, _TCHAR* argv[])
{
    Base* bp = new Base();
    Derived* dp = new Derived();
    bp->Display();
    dp->Display(true);
    bp = new Derived();
    bp->Display();
    cout<<"Done"<<endl;
    return 0;
}
#include "stdafx.