#include<stdio.h>
int main(void){
int a[3] = {1,2,3};
int *p;
p = &a+2;
// here p and &a+2 will going to be same...having some particular address on memory
*p = 56;
// m writing 56 on *(p) or *(&a+2)...
printf("%d %d\n",*p,*(&a+2));
return 0;
}
#include<stdio.h>
int main(void){
int a[3