list.sort实现根据对象的属性值对集合进行排序_u013367040的博客

list.sort实现根据对象的属性值对集合进行排序，如下所示


List<Map<String,Object>> list = new ArrayList<>();
Map<String,Object> map1 = new HashMap<>();
map1.put("gz_id",1);
map1.put("aaa","aaa");
Map<String,Object> map2 = new HashMap<>();
map2.put("gz_id",2);
map2.put("aaa","bbb");
Map<String,Object> map3 = new HashMap<>();
map3.put("gz_id",3);
map3.put("aaa","ccc");
list.add(map3);
list.add(map2);
list.add(map1);
Map<String,Object> map4 = new HashMap<>();
map4.put("gz_id",4);
map4.put("aaa","aaa1");
list.add(map4);
System.out.println(list.get(0).get("gz_id"));
System.out.println(list.get(1).get("gz_id"));
System.out.println(list.get(2).get("gz_id"));
System.out.println(list.get(3).get("gz_id"));
list.sort((o1, o2) -> {
    int type1 = (int) o1.get("gz_id");
    int type2 = (int) o2.get("gz_id");
    return type1 - type2;
});
System.out.println("---------");
System.out.println(list.get(0).get("gz_id"));
System.out.println(list.get(1).get("gz_id"));
System.out.println(list.get(2).get("gz_id"));
System.out.println(list.get(3).get("gz_id"));list.sort实现根据对象的属性值对集合进行排序，如下所示


List<Map&l