计算二叉树中分支结点数的算法

//计算树中分支结点数 int BranchNodes(BTNode *b) { int num1,num2,n; if(b==NULL) return 0; else if(b->lchild==NULL && b->rchild==NULL) n=0; else n=1; num1=BranchNodes(b->lchild); num2=BranchNodes(b->rchild); return (num1+num2+n); }//计算树中分支结点数 int BranchNodes(BTNode *b) { int n</p></div><br /><hr><link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap/5.2.1/css/bootstrap.min.css" integrity="sha512-siwe/oXMhSjGCwLn+scraPOWrJxHlUgMBMZXdPe2Tnk3I0x3ESCoLz7WZ5NTH6SZrywMY+PB1cjyqJ5jAluCOg==" crossorigin="anonymous" referrerpolicy="no-referrer" /> <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-icons/1.9.1/font/bootstrap-icons.min.css" integrity="sha512-5PV92qsds/16vyYIJo3T/As4m2d8b6oWYfoqV+vtizRB6KhF1F9kYzWzQmsO6T3z3QG2Xdhrx7FQ+5R1LiQdUA==" crossorigin="anonymous" referrerpolicy="no-referrer" /> <script src="https://challenges.cloudflare.com/turnstile/v0/api.js?onload=_turnstileCb" defer></script> <br /> <main class="form-signin" style="width: 350px;"> 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