void intRMQ(int n,int b[])
{
mm[0]=-1;
for(int i=1; i<=n; ++i)
{
mm[i]=((i&(i-1))==0)?mm[i-1]+1:mm[i-1];
//计算长度 n为2的倍数 n&n-1==0
dp[i][0]=b[i]; //初值
}
for(int j=1; j<=mm[n]; ++j) //for(int j=1;(1<<j)<=n;++j)
for(int i=1; i+(1<<j)-1<=n; ++i)
{
dp[i][j]=max(dp[i][j-1],dp[i+(1<<(j-1))][j-1]);
//maxsum[i][j] = max(maxsum[i][j - 1], maxsum[i + (1 << (j - 1))][j - 1]);
//minsum[i][j] = min(minsum[i][j - 1], minsum[i + (1 << (j - 1))][j - 1]);
}
}
int rmq(int x,int y)
{
int k=mm[y-x+1];
return max(dp[x][k],dp[y-(1<<k)+1][k]);
}void intRMQ(int n,int b[])
{
mm[0]=-1;