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在输入字段中显示AJAX响应

来源:互联网 
<table class="table table-bordered responsive">
          <thead>
            <tr>
              <th>Session</th>
              <th>Bus Route</th>
              <th>Charges</th>
              <th>Action</th>
            </tr>
          </thead>
          <?php foreach ($fetchbus as $busfee){?>
          <tbody>
            <form action="#" method="post">
              <tr>
                <td> <?php echo $busfee->Session; ?> </td>
                <td> <?php echo $busfee->Route; ?> </td>
                <td> <?php echo $busfee->Charges; ?> </td>
                <td><a href="/go.html?url=#" id="<?php echo $row->Route_Id;?>" onClick="getbusdetailsforedit(this.id)" class="">Edit</a></td>
              </tr>
              <script type="text/javascript">
                function getbusdetailsforedit(id)
                {
                  ajaxRequest = new XMLHttpRequest();
                  ajaxRequest.onreadystatechange = function()
                  {
                    if(ajaxRequest.readyState == 4)
                    {
                      var ajaxDisplay = document.getElementById('getbusdetailsforeditview');
                      ajaxDisplay.innerHTML = ajaxRequest.responseText;    
                    }
                  }
                  ajaxRequest.open("GET", "<?php echo base_url();?>account/SetFee/getbusdetailsforedit/" +id, true);
                  ajaxRequest.send(); 

                } 
              </script> 
            </form>
          </tbody>
          <?php } ?>
        </table> 
<table class="table table-bordered responsive">



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