阅读背景:

用于亚马逊卷曲数据的Ruby重构器

来源:互联网 

Is there a more efficient way to get this done? By this I mean can I refactor my script to get the outcome more efficiently, not getting this info from another source ie. Amazon via API or SDK.Is there a more efficient way to get this done?




你的当前访问异常,请进行认证后继续阅读剩余内容。

分享到: