用C语言设计一个简单计算器

p=1 s;int i=1 er sum d c b #include <iostream.h>#include <math.h>main(){ float a 自己找 j;char t;while(p==1) { cout<<"算式：(a表示x的y次方；s表示开方; c清零)"<<endl; cin>>a>>t; if(t=='+') {cin>>b;c=a+b;} else if(t=='-') {cin>>b;c=a-b;} else if(t=='*') {cin>>b;c=a*b;} else if(t=='/') {cin>>b;c=a/b;} else if(t=='a') { c=1; cin>>b; for(j=0;j<b;j++) { c=c*a; } } else if (t=='s') c=sqrt(a); else if (t=='c') continue; cout<<c; sum=c; while(i==1) {cin>>t; if(t=='+') {cin>>d;sum=sum+d;} else if(t=='-') {cin>>d;sum=sum-d;} else if(t=='*') {cin>>d;sum=sum*d;} else if(t=='/') {cin>>d;sum=sum/d;} else if(t=='a') { s=1; cin>>d; for(j=0;j<b;j++) { s=s*sum; } sum=s; } else if (t=='s') sum=sqrt(sum); else {break;} cout<<sum ;}} cin>>er;} |||来这里下载吧 多的很 找一个适合你的就OK https://search.download.csdn.net/search/C%E8%AF%AD%E8%A8%80%E8%AE%A1%E7%AE%97%E5%99%A8|||百度上面搜去一大堆 看不懂我可以帮你写注释 p=1 s;int i=1 er sum d c b #include <iostream.h