我如何为基础类型int的枚举专门化一个类?

#include <type_traits>

enum class MyEnum
{
    Hello
};

template <typename T, typename Enable = void>
class MyClass
{
public:
    MyClass(T obj) : e(obj)
    {}

private:
    T e;
};

template <typename T>
class MyClass <T, 
    typename std::enable_if< std::is_enum<T>::value 
                             && std::is_same<typename std::underlying_type<T>::type, 
                                             int>::value>::type > 
{
public:
    MyClass(T obj) : e(obj)
    {}

private:
    T e;
};

int main()
{
    MyClass<MyEnum> c(MyEnum::Hello);
    MyClass<int> c1(1); //does not compile due to std::underlying_type
    return 0;
}
#include <type_traits>

enum class MyEnum
{