阅读背景:

为什么名称相同但签名不同的多继承函数不被视为重载函数?

来源:互联网 

The following snippet produces an "ambigious call to foo" error during compilation, and I'd like to know if there is any way around this problem without fully qualifying the call to foo:The following snippet produces an "ambigious ca




你的当前访问异常,请进行认证后继续阅读剩余内容。

分享到: