When I create a new WPF application in Visual Studio 2012 the platform target and build configuration is set to x86 by default. Why is this the case? For a plain WPF application (without any references to mixed mode assemblies) is there any danger using AnyCPU so my WPF executable will be JITed to x64 code on my x64 machine and to x86 on a x86 machine?When I create a new WPF application in Visual S