sql 递归查询，查出所有子节点

with t as
(
  select b.* from Base_Department b where ParentId = 'cce4152c-3483-4334-b68d-155da627bca0' 
  union all
  select a.* from Base_Department a join t b on a.ParentId=b.DepartmentId
)
select * from t
with t as
(
  select b.* from Base_Departme