使用集合列表创建数组

I have this,

我有这个，

    srand( ( unsigned) 0 );
    for( n = 0; n < len; ++n )  
     {                          
         word[ n ] = 'a' + rand( ) % ;

     }
     word[ n ] = '
 
 
I have this, 
 
 
我有这个，
 
 
    srand( ( unsigned) 0 );
    for( n = 0; n < len; ++n )  
     {                          
         word[ n ] = 'a' + rand( ) % ;

     }
     word[ n ] = '\0';
 
 
and i need it to select the random characters from a set list of non consecutive, characters, B,H,G,K,V and fill the string with the characters selected. What I don't know how to do is get my program to select from only those few characters
 
 
我需要它从非连续，字符，B，H，G，K，V的集合列表中选择随机字符，并用所选字符填充字符串。我不知道怎么办是让我的程序只从那几个字符中选择
 
  
  
 
1 个解决方案
 
 
 
  
#1
 
  
 
  
 
   
2  
 
   
Generate an integer between 0 and 4 (last index of [B,H,G,K,V]).
 
   
生成0到4之间的整数（[B，H，G，K，V]的最后一个索引）。
 
   
Then use this random integer to index into an array of your characters:
 
   
然后使用此随机整数索引到您的字符数组：
 
   
static const char letters[] = "BHGKV"; //your letters as a string
word[n] = letters[rand() % 5]; //get a random letter from letters
 
   
Note, rand() % 5 may not be the best way to generate a random number in a range.
 
   
注意，rand（）％5可能不是在范围内生成随机数的最佳方法。
 
  
 
 
 

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    srand( ( unsigned)