使用单个循环如何从给定的单个链表打印最后的第3个元素？

With single loop how can we print last 3rd element from given single linked list lets take there are 10 node in give linked list and i am supposed to find last 3rd node? below code is for inserting a node at beginning now how can i print last 3rd element with sing loop? please help me With single loop how can we print last 3rd elem