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如何只为我需要的信息轻松解析返回的JSON对象?

来源:互联网 

Using the following snippet of code, I can get 4 results from the google Web Search API. I know I'm using a deprecated API, but I'm only testing something here and will use the new Custom Search API when I'm more familiar with it. For now, though, I was wondering how I can parse the returned result for the "unescapedUrl" that is in the result? Basically, I want to grab all four of the "unescapedUrl" values in the returned JSON.Using the following snippet of code, I can get




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