如何在查询和显示表中的数据时使用PHP函数返回的值？

Am attempting to display test results of multiple students in a class. To do this, am using a function find_student_by_year($year) to get a list of all the students which includes the student id. The id is then used in an sql statement to query the result for the specific student id. My code isn't throwing errors but no data is displayed even though the table actually has data. Unfortunately, my research has shown nothing similar so no link is added to my post. See code am working with belowAm attempting to display test results of multip