阅读背景:

如何在视图2中的php代码块中读取过滤器变量?

来源:互联网 

I'm trying to create an img link manually with php in the header field of a view, in drupal 6. I need to read the value of one of the filters, but can't find the right variable to read. I thought I could print_r($view->filters) but it didn't give me anything, and I eventually found out that isset($view) is false.I'm trying to create an img link manually with




你的当前访问异常,请进行认证后继续阅读剩余内容。

分享到: