阅读背景:

如何在Android中使用JSON将微调器值发送到服务器?

来源:互联网 

I am new on Android. I am not able to send spinner value to jsonobject. I am getting an error: "selected cannot be resolved to a variable". Following is my code. Please tell me what I need to do. Thanks in advance. I am new on Android. I am not able to send spin




你的当前访问异常,请进行认证后继续阅读剩余内容。

分享到: