如何使这个有条件的谜题实例方法更加Ruby惯用？

  def short_remaining_time
    difference  = Time.diff(Time.now, created_at + 7.days, '%d - %H - %N')

    # To display the short remaining time in an auction listing.
    if difference[:day] == 0 and difference[:hour] >= 1
      "#{difference[:minute]} minutos"
    elsif difference[:day] == 0 and difference[:hour] >= 23
      "#{difference[:hour]} horas"
    else
      if difference[:day] != 1
        "#{difference[:day]} dias"
      else
        "#{difference[:day]} dia"
      end
    end
  end
  def short_remaining_time
    difference  = Ti