如何将字符串赋值为char *指针？

#include <stdio.h>

struct Analysis {
    int lnlen;   
    int arr[2]; 
    char* name;
};

int main()
{
    struct Analysis ana_space[2];
    char *ptr = (void*) &ana_space;

    ana_space[0].lnlen = 0;
    ana_space[0].arr[0] = 1;
    ana_space[0].arr[1] = 2;
    ana_space[0].name = "Peter";

    printf("\n%d\n", *ptr);     // print 0;

    *ptr = 10;                  // how to use memcpy here;

    printf("\n%d\n", *ptr);     // print 10;

    ptr = ptr + sizeof(int);    // advance pointer by int;

    printf("\n%d\n", *ptr);     // print 1;  

    ptr = ptr + 2*sizeof(int);  // advance pointer by 2 ints;

    printf("\n%s\n", *ptr);     // print "Peter"; --------------not work

    //*ptr = "Jim";             // how to assign new name "Jim" into that memory;
    return 0;
}
#include <stdio.h>

struct Analysis {
    int l