如何将对象的副本传递给$ .ajax的.done（）函数？

I have the following code:

我有以下代码:

function doDialogAjax(link: Link. modal: Modal) {
    $.ajax( link.Url,
    {
        cache: false,
        dataType: 'html'
    })
        .done(onDialogDone)
        .fail(onDialogFail);
}

function onDialogDone(data: any, textStatus: string, jqXHR: JQueryXHR) {
    var x = data;
    // I need to access link.abc and modal.def properties here
}
function