如何获取已在PHP函数内声明的变量的值并将其返回到外部

function count($data) {
    $json = file_get_contents( 'https://api.facebook.com/restserver.php?method=links.getStats&format=json&urls=' . $data . '&pretty=1' );
    $json_data = json_decode($json, true);
    $count = $json_data[0]['total_count'];
    if(empty ($count) ) {
        return 'n/a';
    } else {
        if( $count < 1000 ) return $count;
        $x = round($count);
        $x_number_format = number_format($x);
        $x_array = explode(',', $x_number_format);
        $x_parts = array('k', 'm', 'b', 't');
        $x_count_parts = count($x_array) - 1;
        $x_display = $x;
        $x_display = $x_array[0] . ((int) $x_array[1][0] !== 0 ? '.' . $x_array[1][0] : '');
        $x_display .= $x_parts[$x_count_parts - 1];
        return  $x_display;
    }

}
function count($data) {
    $json = file_get_co