阅读背景:

如何从视图中传递OpenFileDialog结果“FilePath”来查看模型?

来源:互联网 

I am trying to open a file dialog by pressing a button on view and view call a command "OpenFileDialog" which is defined in viewmodel. That method send a message to view to open the "Microsoft.Win32.OpenFileDialog()" and now I want to communicate the result of OpenFileDialog to ViewModel.I am trying to open a file dialog by pressing a




你的当前访问异常,请进行认证后继续阅读剩余内容。

分享到: