python打印一个空心等腰三角形，再内接一个空心三角形

def trangle(number):
    
    for i in range(1,number+1):
        if  i > 1 and i < number:
            if i == number//2+1:
                str1=' '*(number-i)+'* '*i
                '打印内接三角形的底'
            elif i > number//2:
                str1=' '*(number-i)+'*'+' '*(i*2-number-2)+'*'+' '*(2*(number-i)-1)+'*'+' '*(i*2-number-2)+'*'
                '打印内接三角形的腰以及外面的三角形的腰'
            else:
                str1=' '*(number-i)+'*'+' '*((i-1)*2-1)+'*'
            
        else :
            str1=' '*(number-i)+'* '*(i)
        print(str1)
 

trangle(11)
    
def trangle(number):
    
    for i in r