python 计算列表中某个元素连续出现的次数_像风一样的男人@的博客

a = [1, 2, 3, 4, 21, 1, 1, 2, 3, 1, 1, 1]
b = 2			# b的值为要求的数字
t = 0
w = 1
for k, v in enumerate(a):
    if k > 0:
        if v == b and a[k - 1] == b:
            t += 1
            if w < t:
                w = t
        else:
            t = 1
print(w)
a = [1, 2, 3, 4, 21, 1, 1, 2, 3, 1, 1, 1