$source = 'hello';
$fp=fopen ("/tmp/pubkey","r"); $fp=fopen ("/tmp/pubkey","
$fp=fopen ("/tmp/pubkey","r"); $fp=fopen ("/tmp/pubkey","
阅读背景：
openssl_public_encrypt 使用非填充时总是返回false 为什么？
来源：互联网
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