计算给定数组中的偶数和字符

#include <stdio.h> 

int result=0;
void count_even(int*b, int size){
    for (int a = 0; a < size; a++){
        if(b[a] % 2 == 0){
            result++;
        }
    }
}

int main(int argc, char* argc[]){
    int data_array_1[] = {1, 3, 5, 7, 9, 11);
    int data_array_2[] = (2, -4, 6, -8, 10, -12, 14, -16};
    int data_array_2[] = {10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0};

    int result_1 = count_even(data_array_1, 6);
    printf("data_array_1 has%d even numbers\n", result_1);
    int result_2 = count_even(data_array_2, 8);
    printf("data_array_2 has %d even numbers\n", result_2);
    int result_3 = count_even(data_array_3, 11);
    printf("data_array_3 has %d even numbers\n", result_3);
    return 0;
}
#include <stdio.h> 

int result=0;
void count_e