4.关于两个表对应的不匹配查询的正确语句为
A.SELECT [ccode] FROM [GL_accsum] where not exists(SELECT * FROM [code] group by ccode having [ccode]=[GL_accsum].[ccode]) A.SELECT [ccode] FROM
A.SELECT [ccode] FROM [GL_accsum] where not exists(SELECT * FROM [code] group by ccode having [ccode]=[GL_accsum].[ccode]) A.SELECT [ccode] FROM