I have code like that
我有这样的代码
var ajaxrequest = $.ajax({
type: "POST",
dataType: "json",
url: "xy.php",
data: {
action : "read"
}
}).fail(function(){
//something to do when ajaxreq fails
}).done(function(data){
//something to do when ajaxreq is done
});
var ajaxreque