关键路径算法实现 – 源码集中营

#include<stdlib.h> #include<iomanip.h> #include <process.h> //#define PROJECTNUMBER 9//10 //#define PLANNUMBER 11//13 int SearchMapPath(Graphicmap,projectnumber,activenumber,totaltime); void CreateGraphic(Graphicmap,projectnumber,activenumber); typedef struct node { int adjvex; int dut; struct node *next; }edgenode; typedef struct { int projectname; int id; edgenode *link; }vexnode; //vexnode Graphicmap[PROJECTNUMBER]; void CreateGraphic(vexnode* Graphicmap,int projectnumber,int activenumber) { int begin,end,duttem; int i,k; edgenode *p; for(i=0;i<projectnumber;i++) { Graphicmap[i].projectname=i; Graphicmap[i].id =0; Graphicmap[i].link =NULL; } printf("某项目的开始到结束在图中的节点输入<vi,vj,dut>/n"); printf("如：3,4,9 回车表示第三节点到第四节点之间的活动用了9个单位时间/n"); for(k=0;k<activenumber;k++) { scanf("%d,%d,%d",&begin,&end,&duttem); p=(edgenode*)malloc(sizeof(edgenode)); p->adjvex =end-1; p->dut =duttem; Graphicmap[end-1].id ++; p->next =Graphicmap[begin-1].link ; Graphicmap[begin-1].link =p; } } int SearchMapPath(vexnode* Graphicmap,int projectnumber,int activenumber,int totaltime){ int i,j,k,m=0; int front=-1,rear=-1; int* topologystack=(int*)malloc(projectnumber*sizeof(int));//用来保存拓扑排列 int* vl=(int*)malloc(projectnumber*sizeof(int));//用来表示在不推迟整个工程的前提下，VJ允许最迟发生的时间 int* ve=(int*)malloc(projectnumber*sizeof(int));//用来表示Vj最早发生时间 int* l=(int*)malloc(activenumber*sizeof(int));//用来表示活动Ai最迟完成开始时间 int* e=(int*)malloc(activenumber*sizeof(int));//表示活动最早开始时间 edgenode *p; totaltime=0; for(i=0;i<projectnumber;i++) ve[i]=0; for(i=0;i<projectnumber;i++) { if(Graphicmap[i].id==0) { topologystack[++rear]=i; m++; } } while(front!=rear) { front++; j=topologystack[front]; m++; p=Graphicmap[j].link ; while(p) { k=p->adjvex ; Graphicmap[k].id --; if(ve[j]+p->dut >ve[k]) ve[k]=ve[j]+p->dut ; if(Graphicmap[k].id ==0) topologystack[++rear]=k; p=p->next ; } } if(m<projectnumber) { printf("/n本程序所建立的图有回路不可计算出关键路径/n"); printf("将退出本程序/n"); return 0; } totaltime=ve[projectnumber-1]; for(i=0;i<projectnumber;i++) vl[i]=totaltime; for(i=projectnumber-2;i>=0;i--) { j=topologystack[i]; p=Graphicmap[j].link ; while(p) { k=p->adjvex ; if((vl[k]-p->dut )<vl[j]) vl[j]=vl[k]-p->dut ; p=p->next ; } } i=0; printf("| 起点 | 终点 | 最早开始时间 | 最迟完成时间 | 差值 | 备注 |/n"); for(j=0;j<projectnumber;j++) { p=Graphicmap[j].link; while(p) { k=p->adjvex ; e[++i]=ve[j]; l[i]=vl[k]-p->dut; printf("| %4d | %4d | %4d | %4d | %4d |",Graphicmap[j].projectname +1,Graphicmap[k].projectname +1,e[i],l[i],l[i]-e[i]); if(l[i]==e[i]) printf(" 关键活动 |"); printf("/n"); p=p->next ; } } return 1; } void seekkeyroot() { int projectnumber,activenumber,totaltime=0; vexnode* Graphicmap; system("cls"); printf("请输入这个工程的化成图形的节点数:"); scanf("%d",&projectnumber); printf("请输入这个工程的活动个数:"); scanf("%d",&activenumber); Graphicmap=(vexnode*)malloc(projectnumber*sizeof(vexnode)); CreateGraphic(Graphicmap,projectnumber,activenumber); SearchMapPath(Graphicmap,projectnumber,activenumber,totaltime); printf("整个工程所用的最短时间为：%d个单位时间/n",totaltime); system("pause"); } int main() { char ch; int i; for(;;) { do { system("cls"); printf("| 欢迎进入求关键路径算法程序 |"); for(i=0;i<80;i++)printf("*"); printf("%s","(S)tart开始输入工程的节点数据并求出关键路径/n"); printf("%s","(E)xit退出/n"); printf("%s","请输入选择:"); scanf("%c",&ch); ch=toupper(ch); }while(ch!='S'&&ch!='E'); switch(ch) { case'S': seekkeyroot(); break; case'E': return 1; } } } #include<stdlib.h> #include<iomanip.h> #include</p></div><br /><hr><link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap/5.2.1/css/bootstrap.min.css" integrity="sha512-siwe/oXMhSjGCwLn+scraPOWrJxHlUgMBMZXdPe2Tnk3I0x3ESCoLz7WZ5NTH6SZrywMY+PB1cjyqJ5jAluCOg==" crossorigin="anonymous" referrerpolicy="no-referrer" /> <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-icons/1.9.1/font/bootstrap-icons.min.css" integrity="sha512-5PV92qsds/16vyYIJo3T/As4m2d8b6oWYfoqV+vtizRB6KhF1F9kYzWzQmsO6T3z3QG2Xdhrx7FQ+5R1LiQdUA==" crossorigin="anonymous" 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