更改在表Django中选择了其中一个按钮时显示的状态

May I know why is my status remain unchanged when either "approve" or "deny" button has been selected for that particular row? How can I pass the value that I change in views.py back to my html file in order to print out the status? Should I declare the Action field in models.py since action is just 2 buttons with name of approve and deny?May I know why is my status remain unchanged wh