返回列表中连续的所有子序列的函数

I have this function

我有这个功能

def conseq_sequences(li, length):
    """ Takes a list and a length. Returns all sub-sequences in li that
    are successice (e.g. [1,2,3] or [5,6,7,8]) and of the right length.

    E.g.  >>> conseq_sequences([1,6,7,8,9,8,9], length=3)
          [[6,7,8], [7,8,9]]
    """
    return [li[n:n + length] for n in range(len(li) - length + 1)
            if li[n:n + length] == range(li[n], li[n] + length)]
def conseq_sequ