第九周项目六——年龄

/*文件名称：weq
02.*作者：李明宇
03.*完成日期：2014年10月23日
04.*版本号：v1.0
05.*问题描述：四个人的年龄成等差数列，他们年龄相加为26，相乘是880，求以他们的年龄为前四项的等差数列的前20项
06.*输入描述：
07.*输出：前二十项






*/# include<iostream>
using namespace std;
int main()
{


    int a,n,count=0;
    cout<<"等差数列为："<<endl;
    for (a=1; a<=4; a++)
        for (n=1; n<=6; n++)
            if((4*n+6*a==26)&&(n*(n+a)*(n+a+a)*(n+a+a+a)==880))
            {
                ++count;
                cout<<count<<":"<<n<<","<<n+a<<","<<n+a*2<<","<<n+a*3<<","<<n+a*4<<","<<n+a*5;
                cout<<","<<n+a*6<<","<<n+a*7<<","<<n+a*8<<","<<n+a*9<<","<<n+a*10<<","<<n+a*11;
                cout<<","<<n+a*12<<","<<n+a*13<<","<<n+a*14<<","<<n+a*15<<","<<n+a*16<<","<<n+a*17;
                cout<<","<<n+a*18<<","<<n+a*19<<","<<n+a*20<<endl;
            }
    return 0;
}
/*文件名称：weq
02.*作者：李明宇
03.*完成日期：2014年10月23日
04.*