阅读背景：

第八周——运算符重载——项目四 字符串类

来源：互联网 

问题及代码：

/*    
*Copyright (c) 2014,烟台大学计算机学院    
*All rights reserved.    
*文件名称:lily.cpp    
*作者:李莉    
*完成日期:2015年4月25日    
*版本号:v1.0    
*   
*问题描述：实现运算符重载处理字符串
*程序输入：无输入  
*程序输出：如结果图  
*/
#include <iostream>
#include <Cstring>
using namespace std;
class String
{
public:
    String ( );
    String (const char *s);
    String (String &str);
    ~String ();
    void display();
    friend String operator +(String &s1,String &s2);
    friend String operator -(String &s1,String &s2);
private:
    char *p;   //指向存储的字符串
    int len;   //记录字符串的长度
};
String::String()
{
    len=0;
    p=NULL;
}
String::String(const char *s)
{
    len=strlen(s);
    p=new char[len+1];
    strcpy(p,s);
}
String::String(String &str)
{
    len=str.len;
    if(p!=NULL) delete []p;
    p=new char[len+1];
    strcpy(p,str.p);
}
String::~String()
{
    if(!p)delete []p;
}
void String::display()
{
    cout<<p<<endl;
}
String operator +(String &s1,String &s2 )
{
    String s;
    s.len=s1.len+s2.len;
    s.p=new char[s.len+1];
    strcpy(s.p,s1.p);
    strcat(s.p,s2.p);
    return s;
}
String operator - (String &s1, String &s2 )
{
    String s;
    char *c1=new char[s1.len+1];
    strcpy(c1,s1.p);
    int i=s1.len-1;
    while(i>=0&&c1[i]==' ')
    {
        --i;
    }
    c1[i+1]='
 
 
问题及代码：
 
 
/*    
*Copyright (c) 2014,烟台大学计算机学院    
*All rights reserved.    
*文件名称:lily.cpp    
*作者:李莉    
*完成日期:2015年4月25日    
*版本号:v1.0    
*   
*问题描述：实现运算符重载处理字符串
*程序输入：无输入  
*程序输出：如结果图  
*/
#include <iostream>
#include <Cstring>
using namespace std;
class String
{
public:
    String ( );
    String (const char *s);
    String (String &str);
    ~String ();
    void display();
    friend String operator +(String &s1,String &s2);
    friend String operator -(String &s1,String &s2);
private:
    char *p;   //指向存储的字符串
    int len;   //记录字符串的长度
};
String::String()
{
    len=0;
    p=NULL;
}
String::String(const char *s)
{
    len=strlen(s);
    p=new char[len+1];
    strcpy(p,s);
}
String::String(String &str)
{
    len=str.len;
    if(p!=NULL) delete []p;
    p=new char[len+1];
    strcpy(p,str.p);
}
String::~String()
{
    if(!p)delete []p;
}
void String::display()
{
    cout<<p<<endl;
}
String operator +(String &s1,String &s2 )
{
    String s;
    s.len=s1.len+s2.len;
    s.p=new char[s.len+1];
    strcpy(s.p,s1.p);
    strcat(s.p,s2.p);
    return s;
}
String operator - (String &s1, String &s2 )
{
    String s;
    char *c1=new char[s1.len+1];
    strcpy(c1,s1.p);
    int i=s1.len-1;
    while(i>=0&&c1[i]==' ')
    {
        --i;
    }
    c1[i+1]='\0';
    char *c2=new char[s2.len+1];
    strcpy(c2,s2.p);
    i=0;
    while(i<s2.len&&c2[i]==' ')
    {
        ++i;
    }
    int j=0;
    while(i<s2.len&&c2[i]!='\0')
    {
        c2[j]=c2[i];
        ++i;
        ++j;
    }
    c2[j]='\0';
    s.len = strlen(c1)+strlen(c2);
    s.p = new char[s.len+1];
    strcpy(s.p,c1);
    strcat(s.p,c2);
    delete c1;
    delete c2;
    return s;
}
int main()
{
    String string1(" Hello  "), string2(" World ");
    string1.display();
    string2.display();
    String string3;
    string3=string1 + string2;
    string3.display();
    string3=string1 - string2;
    string3.display();
    return 0;
}

 
 

 运行结果：
 
 
 
  
  
 
心得体会：
 
 
我差点纠结死！！！已经疯了！！字符串给跪了！！我准备重做之前的项目了！！/(ㄒoㄒ)/~~
 
 
 
 


';
    char *c2=new char[s2.len+1];
    strcpy(c2,s2.p);
    i=0;
    while(i<s2.len&&c2[i]==' ')
    {
        ++i;
    }
    int j=0;
    while(i<s2.len&&c2[i]!='
 
 
问题及代码：
 
 
/*    
*Copyright (c) 2014,烟台大学计算机学院    
*All rights reserved.    
*文件名称:lily.cpp    
*作者:李莉    
*完成日期:2015年4月25日    
*版本号:v1.0    
*   
*问题描述：实现运算符重载处理字符串
*程序输入：无输入  
*程序输出：如结果图  
*/
#include <iostream>
#include <Cstring>
using namespace std;
class String
{
public:
    String ( );
    String (const char *s);
    String (String &str);
    ~String ();
    void display();
    friend String operator +(String &s1,String &s2);
    friend String operator -(String &s1,String &s2);
private:
    char *p;   //指向存储的字符串
    int len;   //记录字符串的长度
};
String::String()
{
    len=0;
    p=NULL;
}
String::String(const char *s)
{
    len=strlen(s);
    p=new char[len+1];
    strcpy(p,s);
}
String::String(String &str)
{
    len=str.len;
    if(p!=NULL) delete []p;
    p=new char[len+1];
    strcpy(p,str.p);
}
String::~String()
{
    if(!p)delete []p;
}
void String::display()
{
    cout<<p<<endl;
}
String operator +(String &s1,String &s2 )
{
    String s;
    s.len=s1.len+s2.len;
    s.p=new char[s.len+1];
    strcpy(s.p,s1.p);
    strcat(s.p,s2.p);
    return s;
}
String operator - (String &s1, String &s2 )
{
    String s;
    char *c1=new char[s1.len+1];
    strcpy(c1,s1.p);
    int i=s1.len-1;
    while(i>=0&&c1[i]==' ')
    {
        --i;
    }
    c1[i+1]='\0';
    char *c2=new char[s2.len+1];
    strcpy(c2,s2.p);
    i=0;
    while(i<s2.len&&c2[i]==' ')
    {
        ++i;
    }
    int j=0;
    while(i<s2.len&&c2[i]!='\0')
    {
        c2[j]=c2[i];
        ++i;
        ++j;
    }
    c2[j]='\0';
    s.len = strlen(c1)+strlen(c2);
    s.p = new char[s.len+1];
    strcpy(s.p,c1);
    strcat(s.p,c2);
    delete c1;
    delete c2;
    return s;
}
int main()
{
    String string1(" Hello  "), string2(" World ");
    string1.display();
    string2.display();
    String string3;
    string3=string1 + string2;
    string3.display();
    string3=string1 - string2;
    string3.display();
    return 0;
}

 
 

 运行结果：
 
 
 
  
  
 
心得体会：
 
 
我差点纠结死！！！已经疯了！！字符串给跪了！！我准备重做之前的项目了！！/(ㄒoㄒ)/~~
 
 
 
 


')
    {
        c2[j]=c2[i];
        ++i;
        ++j;
    }
    c2[j]='
 
 
问题及代码：
 
 
/*    
*Copyright (c) 2014,烟台大学计算机学院    
*All rights reserved.    
*文件名称:lily.cpp    
*作者:李莉    
*完成日期:2015年4月25日    
*版本号:v1.0    
*   
*问题描述：实现运算符重载处理字符串
*程序输入：无输入  
*程序输出：如结果图  
*/
#include <iostream>
#include <Cstring>
using namespace std;
class String
{
public:
    String ( );
    String (const char *s);
    String (String &str);
    ~String ();
    void display();
    friend String operator +(String &s1,String &s2);
    friend String operator -(String &s1,String &s2);
private:
    char *p;   //指向存储的字符串
    int len;   //记录字符串的长度
};
String::String()
{
    len=0;
    p=NULL;
}
String::String(const char *s)
{
    len=strlen(s);
    p=new char[len+1];
    strcpy(p,s);
}
String::String(String &str)
{
    len=str.len;
    if(p!=NULL) delete []p;
    p=new char[len+1];
    strcpy(p,str.p);
}
String::~String()
{
    if(!p)delete []p;
}
void String::display()
{
    cout<<p<<endl;
}
String operator +(String &s1,String &s2 )
{
    String s;
    s.len=s1.len+s2.len;
    s.p=new char[s.len+1];
    strcpy(s.p,s1.p);
    strcat(s.p,s2.p);
    return s;
}
String operator - (String &s1, String &s2 )
{
    String s;
    char *c1=new char[s1.len+1];
    strcpy(c1,s1.p);
    int i=s1.len-1;
    while(i>=0&&c1[i]==' ')
    {
        --i;
    }
    c1[i+1]='\0';
    char *c2=new char[s2.len+1];
    strcpy(c2,s2.p);
    i=0;
    while(i<s2.len&&c2[i]==' ')
    {
        ++i;
    }
    int j=0;
    while(i<s2.len&&c2[i]!='\0')
    {
        c2[j]=c2[i];
        ++i;
        ++j;
    }
    c2[j]='\0';
    s.len = strlen(c1)+strlen(c2);
    s.p = new char[s.len+1];
    strcpy(s.p,c1);
    strcat(s.p,c2);
    delete c1;
    delete c2;
    return s;
}
int main()
{
    String string1(" Hello  "), string2(" World ");
    string1.display();
    string2.display();
    String string3;
    string3=string1 + string2;
    string3.display();
    string3=string1 - string2;
    string3.display();
    return 0;
}

 
 

 运行结果：
 
 
 
  
  
 
心得体会：
 
 
我差点纠结死！！！已经疯了！！字符串给跪了！！我准备重做之前的项目了！！/(ㄒoㄒ)/~~
 
 
 
 


';
    s.len = strlen(c1)+strlen(c2);
    s.p = new char[s.len+1];
    strcpy(s.p,c1);
    strcat(s.p,c2);
    delete c1;
    delete c2;
    return s;
}
int main()
{
    String string1(" Hello  "), string2(" World ");
    string1.display();
    string2.display();
    String string3;
    string3=string1 + string2;
    string3.display();
    string3=string1 - string2;
    string3.display();
    return 0;
}
/*    
*Copyright (c) 2014,烟台大学计算机学院


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