处理这个正则表达式中的空格

This regex

var reg = <font[^>]*>(?:\s*<(\w+)>\s*<\/
 
 
This regex
 
 
var reg = <font[^>]*>(?:\s*<(\w+)>\s*<\/\1>\s*|\s*)<\/font>
 
 
is being used in replace(reg, '') to remove empty font tags. It removes this
 
 
正在替换(reg,'')以删除空字体标记。它删除了这个
 
 
<font size="3"></font>
 
 
okay.
 
 
How can I modify it so it will remove
 
 
如何修改它以便删除
 
 
<font size="3"> </font>
 
 
or
 
 
<font size="3">&nbsp;</font>
 
 
or
 
 
<font size="3">    </font>
 
 
I want to be able to find all empty font tags with any number of spaces between the tags and replace with an empty string.
 
 
我希望能够找到标签之间有任意数量空格的所有空字体标签,并用空字符串替换。
 
  
  
 
2 个解决方案
 
 
 
  
#1
 
  
 
  
 
   
0  
 
   
If all you want to do is find all empty font tags with any number of spaces between the tags and replace with an empty string, you can simplify your regex a bit. If as you've indicated with your current regex, you also want to catch one layer of empty tags within it, you can do as follows:
 
   
如果你想要做的就是找到所有空字体标签,标签之间有任意数量的空格,并用空字符串替换,你可以稍微简化你的正则表达式。如果您已经使用当前的正则表达式进行了指示,那么您还希望在其中捕获一层空标记,您可以执行以下操作:
 
   
 
   
 
    
 
     
var reg = /<font[^>]*>(?:\s|&nbsp;|<(\w+)>(?:\s|&nbsp;)*<\/\1>)*<\/font>/gi

var testStr = `<font size="3"></font>
<font size="3"> </font>
<font size="3">&nbsp;</font>
<font size="3">&nbsp;&nbsp;&nbsp; </font>
<font size="3">    </font>
<font size="3"><something>&nbsp;&nbsp;</something></font>`

console.log(testStr.replace(reg, ""))
 
    
 
   
 
   
 
  
 
 
 
 
 
  
#2
 
  
 
  
 
   
0  
 
   
try this
 
   
<font[^>]*>(?:\s*<(\w+)>\s*<\/\1>\s*|\s*|(&nbsp;)+)<\/font>
 
   
as per your regex. it already catches spaces. I just added the nbsp;
 
   
根据你的正则表达式。它已经占据了空间。我刚加入了
 
   
regex101 link: https://regex101.com/r/4Msyv1/2
 
   
regex101链接:https://regex101.com/r/4Msyv1/2
 
  
 
 
 

>\s*|\s*)<\/font>
var reg = <font[^>]*>(?:\s*<(\w+)>