编写可访问Django数据库功能的Python程序的最简单方法

I have a website which fetches information from RSS feeds periodically (well, currently manually, and this is my problem). This is currently implemented as a normal Django view, which isn't very nice in my opinion. I'd like to have a Python program which is run using a cronjob instead of manually visiting the correct URL to update the information.I have a website which fetches information from