保留两个字符串的公共前缀... C编程...分段故障错误

char *strip_postfix(char *str1, char *str2)
{
   int i;

   for(i=0; str2[i] != '
 
 
char *strip_postfix(char *str1, char *str2)
{
   int i;

   for(i=0; str2[i] != '\0'; i++)
   {
      if(str1[i] != str2[i])
      {
         str1[i] = '\0';
         break;
      }
   }
   return str3;
}
 
 
This code, is giving segmentation fault error at line str1[i] = '\0' during run time..... I think there is some memory allocation issue,, as while I create a new variable and copy the contents there, and then return that new variable, everything works fine.... Please let me know what's the issue in this.
 
 
此代码在运行时在行str1 [i] ='\ 0'给出分段错误错误.....我认为存在一些内存分配问题,因为当我创建一个新变量并将内容复制到那里时,然后返回那个新变量,一切正常....请告诉我这是什么问题。
 
  
  
 
2 个解决方案
 
 
 
  
#1
 
  
 
  
 
   
4  
 
   
What happens if str1 is smaller than str2?
 
   
如果str1小于str2会发生什么?
 
   
You also have:
 
   
你还有:
 
   
return str3;
 
   
Which makes me think this code will not compile in its current form...
 
   
这让我觉得这段代码不会以当前形式编译......
 
  
 
 
 
 
 
  
#2
 
  
 
  
 
   
0  
 
   
Your code should like
 
   
你的代码应该是
 
   
int str1len =  strlen(str1);    
for(i=0; str2[i] != '\0'; i++)
   {
      if(str1[i] != str2[i] || i >= str1len)
      {
         str1[i] = '\0';
         break;
      }
   }
return str1;
 
   
Thanks
 
  
 
 
 

'; i++)
   {
      if(str1[i] != str2[i])
      {
         str1[i] = '
 
 
char *strip_postfix(char *str1, char *str2)
{
   int i;

   for(i=0; str2[i] != '\0'; i++)
   {
      if(str1[i] != str2[i])
      {
         str1[i] = '\0';
         break;
      }
   }
   return str3;
}
 
 
This code, is giving segmentation fault error at line str1[i] = '\0' during run time..... I think there is some memory allocation issue,, as while I create a new variable and copy the contents there, and then return that new variable, everything works fine.... Please let me know what's the issue in this.
 
 
此代码在运行时在行str1 [i] ='\ 0'给出分段错误错误.....我认为存在一些内存分配问题,因为当我创建一个新变量并将内容复制到那里时,然后返回那个新变量,一切正常....请告诉我这是什么问题。
 
  
  
 
2 个解决方案
 
 
 
  
#1
 
  
 
  
 
   
4  
 
   
What happens if str1 is smaller than str2?
 
   
如果str1小于str2会发生什么?
 
   
You also have:
 
   
你还有:
 
   
return str3;
 
   
Which makes me think this code will not compile in its current form...
 
   
这让我觉得这段代码不会以当前形式编译......
 
  
 
 
 
 
 
  
#2
 
  
 
  
 
   
0  
 
   
Your code should like
 
   
你的代码应该是
 
   
int str1len =  strlen(str1);    
for(i=0; str2[i] != '\0'; i++)
   {
      if(str1[i] != str2[i] || i >= str1len)
      {
         str1[i] = '\0';
         break;
      }
   }
return str1;
 
   
Thanks
 
  
 
 
 

';
         break;
      }
   }
   return str3;
}
char *strip_postfix(char *str1, char *str2)
{