>>> match = re.findall('a.*?a', 'a 1 a 2 a 3 a 4 a')
>>> match
['a 1 a', 'a 3 a']
>>> match = re.findall('a.*?a', 'a 1 a 2 a 3 a >>> match = re.findall('a.*?a', 'a 1 a 2 a 3 a 4 a')
>>> match
['a 1 a', 'a 3 a']
>>> match = re.findall('a.*?a', 'a 1 a 2 a 3 a