A.中国式家长2
模拟题,毫无坑点
#include<bits/stdc++.h>
#define REP(i,a,b) for(int i(a);i<=(b);++i)
#define dbg(...) fprintf(stderr,__VA_ARGS__)
using namespace std;
typedef long long ll;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef pair<int,int>pii;
inline int read(){char c,p=0;int w;
while(isspace(c=getchar()));if(c=='-')p=1,c=getchar();
for(w=c&15;isdigit(c=getchar());w=w*10+(c&15));return p?-w:w;
}
template<typename T,typename U>inline char smin(T&x,const U&y){return x>y?x=y,1:0;}
template<typename T,typename U>inline char smax(T&x,const U&y){return x<y?x=y,1:0;}
const int N=202,dx[]={-1,-1,-1,0,1,1,1,0},dy[]={-1,0,1,1,1,0,-1,-1};
int n,m,k,now,nowc,a[N][N];
bool vis[N][N],exi[N][N];
int main(){
n=read(),m=read(),k=read();
REP(i,1,n)REP(j,1,m)a[i][j]=read();
REP(i,1,n)REP(j,1,m)exi[i][j]=read();
int T=read();now=k;
while(T--){
int x=read(),y=read();
if(exi[x][y]&&!vis[x][y]&&x>0&&y>0&&x<=n&&y<=m){
if(a[x][y]>0)now=min(k,now+a[x][y]);
else if(now<10)return puts("-1 -1"),0;
else nowc+=10,now-=10;
vis[x][y]=1;
REP(i,0,7){
int tx=dx[i]+x,ty=dy[i]+y;
if(tx<1||tx>n||ty<1||ty>m)continue;
exi[tx][ty]=1;
}
}else return puts("-1 -1"),0;
}
printf("%d %d\n",now,nowc);
return 0;
}#include<bits/stdc++