MYSQL 关于两个经纬度之间的距离由近及远排序

select *,(2 * 6378.137* ASIN(SQRT(POW(SIN(PI()*(111.86141967773438-lat)/360),2)+COS(PI()*33.07078170776367/180)* COS(lat * PI()/180)*POW(SIN(PI()*(33.07078170776367-lng)/360),2)))) as juli from `area`  select *,(2 *