方法一、
/**
* url参数获取
* @param _params {String} url路径
* @return {Void} 无
*/
getUrlParams(params) {
var url = String(params);
var urlIndex = url.lastIndexOf("?");
if (urlIndex >= 0) {
url = url.substring(urlIndex + 1);
}
var queryString = {};
url.split("&").forEach((item, _index) => {
var index = item.indexOf("=");
if (index) {
queryString[item.substr(0, index)] = item.substr(index + 1);
}
});
return queryString.menuId ? queryString.menuId : ""; //将取到的menuId return出去
},/**
* url参数获取
* @param _params {String}