JAVA学习笔记_判断二位数组是否存在连续4个数的值相同

public class ConsecutiveFour {
	
	public static void main(String[] args) {
		int[][] arr={{0,1,0,6,1,6,1},
				 	 {0,1,6,8,3,0,1},
				 	 {5,8,4,6,8,6,9},
				 	 {6,5,4,8,1,9,7},
				 	 {1,3,7,4,4,4,6},
				 	 {3,3,2,5,4,0,7},
				 	 {1,2,3,3,5,9,7}};
		System.out.println(ConsecutiveFour.isConsecutiveFour(arr));
		
	}
	 public static boolean isConsecutiveFour(int[][] values) {
		    for (int x = 0; x < values.length; x++) {
		      for (int y = 0; y < values[x].length; y++) {
		        if (y >= 3 && equals(values[x][y], values[x][y - 1], values[x][y - 2], values[x][y - 3])) {
		          return true;
		        }
		        if (x >= 3 && equals(values[x][y], values[x - 1][y], values[x - 2][y], values[x - 3][y])) {
		          return true;
		        }
		        if (x >= 3 && y >= 3 && equals(values[x][y], values[x - 1][y - 1], values[x - 2][y - 2], values[x - 3][y - 3])) {
		          return true;
		        }
		        if (x < values.length-3 && y >= 3 && equals(values[x][y], values[x +1][y - 1], values[x + 2][y - 2], values[x + 3][y - 3])) {
			          return true;
			        }
		      }
		    }
		    return false;
		  }

		  private static boolean equals(int... arr) {
		    for (int i = 0; i < arr.length - 1; i++) {
		      if (arr[i] != arr[i + 1]) {
		        return false;
		      }
		    }
		    return true;
		  }
}
public class ConsecutiveFour {
	
	public