阅读背景:

C++判断字符串A是否包含字符串B

来源:互联网 
bool isContain(char *a, char *b){
	int i = 0;
	int j = 0;
	int k = 0;
	
	while(a[i] != '
bool isContain(char *a, char *b){
	int i = 0;
	int j = 0;
	int k = 0;
	
	while(a[i] != '\0' && b[j] != '\0'){
		k = i+1;
		while(b[j] != '\0'){
			if(a[i] == b[j]){
				i++;
				j++;
			}else{
				i = k;
				j = 0;
				break;
			}
		}
	}
	
	return (j != 0);
}
 
  
  

' && b[j] != '
bool isContain(char *a, char *b){
	int i = 0;
	int j = 0;
	int k = 0;
	
	while(a[i] != '\0' && b[j] != '\0'){
		k = i+1;
		while(b[j] != '\0'){
			if(a[i] == b[j]){
				i++;
				j++;
			}else{
				i = k;
				j = 0;
				break;
			}
		}
	}
	
	return (j != 0);
}
 
  
  

'){ k = i+1; while(b[j] != '
bool isContain(char *a, char *b){
	int i = 0;
	int j = 0;
	int k = 0;
	
	while(a[i] != '\0' && b[j] != '\0'){
		k = i+1;
		while(b[j] != '\0'){
			if(a[i] == b[j]){
				i++;
				j++;
			}else{
				i = k;
				j = 0;
				break;
			}
		}
	}
	
	return (j != 0);
}
 
  
  

'){ if(a[i] == b[j]){ i++; j++; }else{ i = k; j = 0; break; } } } return (j != 0); }bool isContain(char *a, char *b){ int i = 0;



你的当前访问异常,请进行认证后继续阅读剩余内容。

分享到: