var specializationTitles = ["a", "b", "c", "d"]
let outputString = join(" / ", specializationTitles)
var specializationTitles = ["a", "b", "c", "d"]
阅读背景：
无法在Swift 2.0中使用类型（String，[String]）的参数列表调用`join`
来源：互联网
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