我们直接用递归来模拟
class Solution {
public static int cnt;
public int uniquePaths(int m, int n) {
cnt = 0;
dfs(1, 1, m, n);
return cnt;
}
public void dfs(int i, int j, int m, int n) {
if (i == m && j == n) {
cnt++;
return;
}
if ((j + 1) <= n)
dfs(i, j + 1, m, n);
if ((i + 1) <= m)
dfs(i + 1, j, m, n);
}
}class Solution {
pu